If sin3A=cos(A-26°)where 3A is an acute angle,find value of A
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Sin3A=cos(A-26)Sin3A=sin263A=26A=26÷3
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SinA= cos(90-A) sin 3A = sin(90-A+26) Sin3A = sin(116-A)3A=116-A4A=116A=116/4A= 29
29
26