If sin theta is = 4/5 find the value of 4 tan theta -5cos theta/ sec theta + 4cot theta
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sin theta=p/h=4/5 so we should find b from this equationb=✓h²-p²✓5²-4²✓25-16✓9=3\xa0\xa0\xa04tan theta – 5 cos theta by sec theta + 4 cot theta4×p/b – 5×b/h divide by h/b + 4×b/p4×4/3 – 5×3/5 divide by 5/3 + 4×3/416/3-3 by 5/3+ 37/3 by 14/33_3cancel7/14=1/2