If sin theta +cos theta=√2 . Then find the value of—– tan theta+ cot theta=?
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here given …sin θ + cos θ = √2we have to findtanθ + cot θ =?solution:-sin θ + cos θ = √2now square on both side= ( sin θ + cos θ )² = √2²= (sin² θ + cos² θ )+ 2 sin θ cos θ = 2= 1+ 2sin θ cos θ = 2=> sin θ cos θ = 1/2nowtanθ + cot θ =sin θ/cos θ + cos θ/sin θ=( sin² θ +cos² θ) / sin θ cos θ= 1 / (1/2) = 2 answer
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