If sin 3A=cos(A-26°),where3A<90°,then the value of A is(a)39°(b)29°(c)49°(d)98°
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Acc to trignometric identities sin 3A can be written as cos ( 90°- 3A) .Now lhs and rhs both are in the form of cos so we can solve the equation by putting of the equations equal
How?
Answer is 29°