It is given that one of the zero of the polynomial x2\xa0- 4x + 1 is (2 + {tex}\\sqrt{3}{/tex}), we have to find the other zero.Let the other zero of the polynomial\xa0x2\xa0- 4x + 1 be\xa0{tex} \\alpha{/tex}.Then, sum of roots =\xa0{tex}-\\frac{(-4)}{1}{/tex}{tex}\\therefore{/tex}\xa02 +\xa0{tex}\\sqrt{3}{/tex}\xa0+\xa0{tex}\\alpha{/tex}\xa0= 4{tex}\\Rightarrow{/tex}\xa0{tex}\\alpha{/tex}\xa0= 2 -\xa0{tex}\\sqrt{3}{/tex}Thus, the other zero\xa0is 2 -\xa0{tex}\\sqrt{3}{/tex}.