If one root of the quadratic equation 3x2 – 10x + p = 0 is \(\frac13\), then the value of p and the other root respectively is :
(a) 3, \(\frac13\)
(b) 3, 3
(c) \(-\frac13\), \(-\frac13\)
(d) –3, –3
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(b) 3, 3
\(\frac13\) is a root of the equation 3x2 – 10x + p = 0
⇒ 3 \(\big(\frac13\big)^2\) – 10 x \(\frac13\) + p = 0
⇒ \(\frac13\) – \(\frac{10}{3}\) + p = 0 ⇒ \(-\frac93\) + p = 0 ⇒ p = 3
∴ The equation becomes 3x2 – 10x + 3 = 0
⇒ 3x2 – 9x – x + 3 = 0
⇒ 3x (x – 3) – 1 (x – 3) = 0 ⇒ (3x – 1)(x – 3) = 0
⇒ x = \(\frac13\), 3
∴ p = 3 and the other root = 3.