If one of the angles of a triangle is 110°, then the angle between the bisectors of the other two angles is
(a) 70° (b) 110° (c) 35° (d) 145°
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If one of the angles of a triangle is 110°, then the angle between the bisectors of the other two angles is
(a) 70° (b) 110° (c) 35° (d) 145°
If one of the angles of a triangle is 110°, then the angle between the bisectors of the other two angles is
(a) 70° (b) 110° (c) 35° (d) 145°
(d) 145o
From the question it is given that, one of the angles of triangle is 110o
We know that, sum of all angles of triangle is equal to 180o.
So, sum of other 2 angles is 180o – 110o = 70o
Then, both angled get halved 70o/2 = 35o
Sum of bisected angles will be half of sum of angle of triangle.
Then, the third angle will be = 180o – 35o
= 145o