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Nishi Natt
Asked: 2022-11-07T10:10:30+05:30 In:

If `N_(t) = N_(o)e^(lambdat)` then number of disintefrated atoms between `t_(1)` to `t_(2) (t_(2) gt t_(1))` will ve :-
A. `N_(o)[e^(lambdat_(2))-e^(lambdat_(3))]`
B. `N_(o)[-e^(lambdat_(2)) – e^(-lambdat_(1))]`
C. `N_(o)[e^(-lambdat_(1)) – e^(-lambdat_(2))]`
D. None of these

If `N_(t) = N_(o)e^(lambdat)` then number of disintefrated atoms between `t_(1)` to `t_(2) (t_(2) gt t_(1))` will ve :-
A. `N_(o)[e^(lambdat_(2))-e^(lambdat_(3))]`
B. `N_(o)[-e^(lambdat_(2)) – e^(-lambdat_(1))]`
C. `N_(o)[e^(-lambdat_(1)) – e^(-lambdat_(2))]`
D. None of these
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1 Answer

  1. Correct Answer – C
    `DeltaN? = N_(1) rarr N_(2) = N_(0)[e^(-lambdat_(1)) – e^(-lambdat_(2))]`

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