If `n=10 , X =12` and `sumx_(12)=1530 ,`then the coefficient of variation is(a) 36% (b) 41% (c) 25% (d) none of these
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Here,` n = 10, barX = 12, sum x_i^2 = 1530`
`:.` Variance `(sigma)^2 = 1/n (sum (x_i^2 – (barX)^2)`
`=>sigma^2 = 1/10(1530 – 10(12)^2) = 90/10 = 9 `
`:.` Standard deviation `(sigma) = sqrt9 = 3`
Now, we will calculate coefficient of variation which is given by,
`C.V. = (sigma)/(barX)**100`
`:. C.V. = 3/12**100 = 25%.`