If `(A)/(mu_(0))` has the dimensions `[MLT^(-4)]` what is A?
A. square of electric flux
B. square of magnitic flux
C. square of electric field
D. square of energy
A. square of electric flux
B. square of magnitic flux
C. square of electric field
D. square of energy
Correct Answer – c
`[(A)/(mu_(0))]= [(epsilon_(0)A)/(epsilon_(0)mu_(0))]= ([epsilon_(0)d])/(1//”speed of light”]^(2)`
`= [ML^(2)T^(-2)]` (Given)
`[epsilon_(0) A] = [ML^(-1)T^(-2)] = ([ML^(2)T^(-2)])/([L^(2)])`
So `epsilon_(0)A` is the energy per volume
Thus A should be `E^(2)`