If a monochromatic light of frequency 6.0×1014 Hz is produced by a source and the power emitted is 2.0×10-3W, then the number of photons emitted per secnod by the source is
(a) 3×1010
(b) 5×1015
(c) 7×1012
(d) 9×1012
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If a monochromatic light of frequency 6.0×1014 Hz is produced by a source and the power emitted is 2.0×10-3W, then the number of photons emitted per secnod by the source is
(a) 3×1010
(b) 5×1015
(c) 7×1012
(d) 9×1012
If a monochromatic light of frequency 6.0×1014 Hz is produced by a source and the power emitted is 2.0×10-3W, then the number of photons emitted per secnod by the source is
(a) 3×1010
(b) 5×1015
(c) 7×1012
(d) 9×1012
Correct Option (b) 5×1015
Explanation :
An energy,
E = hv = 6.63×10–34 x 6.05×1014
= 3.98×10–19J
Now, number of photons emitted per second n = p/E