If a die is tossed, then the probability of getting an odd number or a number greater than 2, is
1. 1/6
2. 2/3
3. 1/3
4. 1/2
5. 5/6
1. 1/6
2. 2/3
3. 1/3
4. 1/2
5. 5/6
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Correct Answer – Option 5 : 5/6
Given:
Die has = 6 numbers
Calculation:
Let O = Event of getting odd number
⇒ {1,3,5}
⇒ Let F = Event of getting a number greater than 2
⇒ {3,4,5,6}
⇒ O ᴒ F = {3,5}
⇒ n(O u F) = n(O) + n(F) – n(O ᴒ F)
⇒ 3 + 4 – 2
⇒ 5
∴ Required Probability = 5/6