If A + B + C = π, Prove that tan A + tan B + tan C = tan A . tanB · tan C
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If A + B + C = π, Prove that tan A + tan B + tan C = tan A . tanB · tan C
If A + B + C = π, Prove that tan A + tan B + tan C = tan A . tanB · tan C
Given A + B + C = π
⇒ A + B = π – C
tan(A + B) = tan(180 – C)
\(\frac{tanA + tanB}{1 – tanA.tanB} = – \frac{tanc}{1}\)
tanA + tanB = – tanc – tanB tanB · tanc
tanA + tanB + tanC = tanA tanB tanC