If a, b and c are in H.P., then the value of `((ac+ab-bc)(ab+bc-ac))/(abc)^2` is
A. `((a+c)(3a-c))/(4a^(2)c^(2))`
B. `(2)/(bc)+(1)/(b^(2))`
C. `(2)/(bc)-(1)/(a^(2))`
D. `((a-c)(3a+c))/(4a^(2)c^(2))`
A. `((a+c)(3a-c))/(4a^(2)c^(2))`
B. `(2)/(bc)+(1)/(b^(2))`
C. `(2)/(bc)-(1)/(a^(2))`
D. `((a-c)(3a+c))/(4a^(2)c^(2))`
Correct Answer – A