If ∆a and ∆b are acute angles such that cos a=cos b, then so that ∆a =∆b.
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Aur vese bhi khud to puchte nhi ho aur dusre ko comment krte hai
Let triangle be abc Cos a=ac/bcCoc b=bc/acHence , Ac/bc=bc/ac Ac=ac A= b
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