If 2x2 cos 60° – 4 cot2 45° – 2 tan 60° = 0, what is the value of x?
(a) 2
(b) 3
(c) √3 – 1
(d) √3 +1
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
If 2x2 cos 60° – 4 cot2 45° – 2 tan 60° = 0, what is the value of x?
(a) 2
(b) 3
(c) √3 – 1
(d) √3 +1
If 2x2 cos 60° – 4 cot2 45° – 2 tan 60° = 0, what is the value of x?
(a) 2
(b) 3
(c) √3 – 1
(d) √3 +1
(d) √3+1
2x2 cos 60° – 4 cot2 45° – 2 tan 60° = 0
⇒ 2x2 x \(\frac12\) – 4 x (1)2 – 2 x √3 = 0
⇒ x2 – 4 – 2√3 = 0 ⇒ x2 = 4 + 2√3
⇒ x2 = 3 + 1 + 2√3 ⇒ x2 = (√3)2 + (1)2 + 2√3
⇒ x2 = (√3 + 1)2 ⇒ x = √3+1.