If `20 cm^(3)` gas at `1 atm` is expanded to `50 cm^(3)` at constant `T`, then what is the final pressure
A. `20xx(1)/(50)`
B. `50xx(1)/(20)`
C. `1xx(1)/(20)xx50`
D. None of these
A. `20xx(1)/(50)`
B. `50xx(1)/(20)`
C. `1xx(1)/(20)xx50`
D. None of these
Correct Answer – A
At constant `T, P_(1)V_(1)=P_(2)V_(2)`
`1xx20= P_(2)xx50, P_(2)=(20)/(50)xx1`