I toss three coins together. The possible outocmes are no heads, 1 head 2 head and 3 heads. So, I say that prbability of no heads is `(1)/(4)`. What is wrong with this conclusion?
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
I toss three coins together
So, total number of outcome `=2^(3)=8`
and possible outcomes are (HHH),(HTT),(THT),(TTH),(HHT),(THH),(HTH),and (TTT)
Now, probability of getting no head=`(1)/(8)`
Hence, the given conclusion is wrong because the probability of no head is `(1)/(8) not (1)/(4)`