How much mass is there approximately in 1 L of mercury (Hg)?
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A volume of 1 L equals 0.001 m3,
the density is in the range of 10000 kg/m3
so we get
m = ρV = 10 000 kg/m3 × 0.001 m3 = 10 kg
A more accurate value is ρ
= 13580 kg/m3.
For the air 1 kg/m3 so we get
m = ρV = 1 kg/m3 × 0.001 m3 = 0.001 kg
A more accurate value is ρ
= 1.17 kg/m3 at 100 kPa, 25°C.