How many two digits no.are divisible by 3 from ch 5
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30
So the ap will be 12,15,18…….99An=99 ,a=12 d=15-12=3An=a+(n-1)d99=12+(n-1)399=12+3n-399=9-3n99-9=3n90=3n90÷3=n30=n There r 30 no.which r divisible by 3