How many three- digits number are divisible by 3?
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369
300
A.P = 102,105,108,………………,999therefore a=102 d=3 an=999 n? an=a+(n-1)d999=102+(n-1)3897=(n-1)3299= n-1n= 299+1n = 300 therefore 300 three digit numbers are divisible by 3.