How many mole of `FeSO_(4),H_(2)C_(2)O_(4)` and `FeC_(2)O_(4)` are oxidised separately by one mole of `KMnO_(4)` in acid medium?
Correct Answer – 1
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
`FeSO_(4)` : `Fe^(2+) rarr Fe^(3+) + e`
`Mn^(7+) + 5e rarr Mn^(2+)`
Thus, `5Fe^(2+) + Mn^(7+) rarr Fe^(3+) + Mn^(2+)`
or `5` mole of `FeSO_(4)` are oxidised by `1` mole `KMnO_(4)`.
`H_(2)C_(2)O_(4)`: `C_(2)^(3+) rarr 2C^(4+) + 2e`
`Mn^(7) + 5e rarr Mn^(2+)`
`5C_(2)^(3+) +2Mn^(7+) rarr 10C^(4+) + 2Mn^(2+)`
or `5//2` mole of `H_(2)C_(2)O_(4)` are oxidised by `1` mole `KMnO_(4)`.
`FeC_(2)O_(4)`: `Fe^(2+) +C_(2)^(3+) rarr Fe^(3+) + 2C^(4+) + 3e`
`Mn^(7+) + 5e rarr Mn^(2+)`
`5FeC_(2)O_(4) +3Mn^(5+) rarr 5Fe^(5+) rarr 5Fe^(3+) + 10C^(4+) + 3Mn^(2+)`
or `5//3` mole of `FeC_(2)O_(4)` are oxidised by `1` mole `KMnO_(4)`.