How many extra electrons are present on a body having 2 coulombs of negative charge?
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Ans. We know the charge on an Electron is\xa0{tex}1.6 \\times 10^{-19} C{/tex}So e =\xa0{tex}1.6 \\times 10^{-19} C{/tex}Total Charge Required q = 2 CSince , q = ne\xa0where n is no of electrons.So, n =\xa0{tex}q\\over e{/tex}\xa0=\xa0{tex}2\\over 1.6 \\times 10^{-19} {/tex}=\xa0{tex}{2 \\times 10^{19} \\over 1.6 }{/tex}\xa0=\xa0{tex}1.25 \\times 10^{19}{/tex}