22338
Given that HCF(306,657)=9, find LCM(306,657)=?
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Given that HCF (306‚657)= 9‚find LCM (306‚657)
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306×657÷9=22338 as HCF×LCM=Product of numbers.
22338
Given that HCF (306,657)=9,find LCM (306,657).
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HCF x LCM = Product of two numbers9 x LCM = 306x657LCM = 306×657/9LCM\xa0= 34 x657LCM = 22338
HCF(306,657)×LCM(657)=306×657LCM(306,657)=201042÷HCF(306,657)LCM(306,657)=201042÷9=22338
Given that HCF(306,657)=9. find LCM(306,657).
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HCF(306,657)=9. So, LCM(306,657)= LCM(306,657)/HCF(306;657) = 306×657/9 = 22338
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HCF of 306,657 , By the procedure calculation method.{tex}HCF =9 \\times 1=9.{/tex}{tex}LCM =9 \\times 1 \\times 73 \\times 34=22338.{/tex}Highest Common Factor is the full form of HCF Least Common Multiple is the full form of LCMThese are done in the above given question, the given is the HCF between two numbers 306, 657 which is 9.\xa0
22338
Given that HCF (306,657)=9.Find LCM (306,657).
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So what????
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LCM is 22338
22338
Given that hcf (306,657)=9 find lcm (306,657)
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HCF×LCM=PRODUCT OF 2 NO.SLCM=PRODUCT OF TWO NO.S/HCFLCM=306×657/9LCM=22338
Given that hcf (306,657)=9 . Find lcm (306,657).
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22338
by formula hcf* lcm= product of two numbers.
Since, LCM(a,b) * HCF(a,b) = a*b Let LCM (306,657) = x So, x * 9 = 306 * 657x = 24538
Given that HCF = 9 and the numbers are 306 and 657 .LCM = ?We know that LCM\xa0× HCF = product of two numbers\xa0⇒LCM\xa0× 9 = 306\xa0× 657⇒LCM = 201042/9 = 22338\xa0
We don\’t need the given part in this question, we can directly find the LCM(306,657) by prime factorisation method.306=2×3×3×17657=3×3×73. So, the LCM of 306 and 657 is2×3×3×17×73=22338