Given an idealgas is expanded adiabatically and irreversibley form volume `V_(1)` to `V_(2))` , then which one of the following is correct ?
A. `DeltaS` ( system ) `= 0 & DeltaS` ( surroundings ) `= + ve`
B. `DeltaS` ( system ) `= +ve & DeltaS` ( surroundings ) `= 0`
C. `DeltaS` ( system ) `= 0 & DeltaS` ( surroundings ) `= 0`
D. `DeltaS` ( system ) `= +ve & DeltaS` ( surroundings ) `= -ve`
A. `DeltaS` ( system ) `= 0 & DeltaS` ( surroundings ) `= + ve`
B. `DeltaS` ( system ) `= +ve & DeltaS` ( surroundings ) `= 0`
C. `DeltaS` ( system ) `= 0 & DeltaS` ( surroundings ) `= 0`
D. `DeltaS` ( system ) `= +ve & DeltaS` ( surroundings ) `= -ve`
Correct Answer – a
For adiabatic process,`q=0` and hence `DeltaS` ( system ) `= 0` . Irrevrsible process is accompaniedby increase of entropy, therefore,`DeltaS` ( surrounding) `= + ve`.