For what value of p are 2p+1,13,5p-3 three consecutive terms of an ap
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Given 2p+1, 13 , 5p-3 are in AP.To find: value of PIf a,b,c are in AP then we know that\xa02b=( a+c)Here a= 2p+1b=13c=5p-32 (13) =(2p+1+5p-3)26=7p-226+2=7p28=7pp=28/7 =4Therefore the value ofP is 4.