For what value of n does the two ap\’s have same value 13,19,25,….&69,68,67,….
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For 1st AP a=13d=19-13=6For 2nd AP A=69D=68-69=-1an =Ana+(n-1)d=A+(n-1)D13+(n-1)6=69+(n-1)-113+6n-6=69-n+17 +6n=70-n6n+n=70-77n=63n=9
9 is the right answer
a1=13d1=6a2=69d2=-113+(n-1)6=69+(n-1)-113+6n-6=69-n+17+6n=70-n7n=63n=9
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