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Ratan Bhai Kurian
Asked: 2022-11-09T00:35:31+05:30 In:

For the reaction,
`2A(g)+B(g) rarr 2D(g)`
`DeltaU^(Θ)=-10.5 kJ` and `DeltaS^(Θ)=-44.1 JK^(-1)`
Calculate `DeltaG^(Θ)` for the reaction, and predict whether the reaction may occur spontaneously.

For the reaction,
`2A(g)+B(g) rarr 2D(g)`
`DeltaU^(Θ)=-10.5 kJ` and `DeltaS^(Θ)=-44.1 JK^(-1)`
Calculate `DeltaG^(Θ)` for the reaction, and predict whether the reaction may occur spontaneously.
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1 Answer

  1. Correct Answer – `0.164 kJ,` the reaction is not spontaneous.
    For the given reaction ,
    `2A_((g))+B_((g))rarr2D_((g))`
    `Deltan_(g)=2-(3)`
    1-mole
    Substituting the value of `Delta^(theta)` in the expression of `DeltaH:`
    `DeltaH^(theta)=DeltaU^(theta)+Deltan_(g)RT`
    `=(-10.5 kJ)-(-1)(8.314xx10^(-3)kJ K^(-1)”mol”^(-1))(298 K)`
    `=-10.5kJ-2.48 kJ`
    `DeltaH^(theta)=-12.98 kJ`
    Subtituting the value of `DeltaH^(theta) and DeltaS^(theta)` in the expression of `DeltaG^(theta):`
    `DeltaG^(theta)=DeltaH^(theta)-TDeltaS^(theta)`
    `=-12.98 kJ -(298 K)(-44.1 j K^(-1))`
    `=-12.98 kJ +13.14 kJ`
    `DeltaG^(theta)=+0.16 kJ`
    Since `DeltaG^(theta)` for the reaction is positive, the reaction will not occur spontaneously.

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