For converting a solution if 100 ml KCl of 0.4 M concentration into a solution of KCl 0.05 M concentration. The quantity of water added is
A. 900 ml
B. 700 ml
C. 500 ml
D. 300 ml
A. 900 ml
B. 700 ml
C. 500 ml
D. 300 ml
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Correct Answer – B
We know that, `M_(1)V_(1)= M_(2)V_(2)`
`0.05xx V_(1)=0.4xx100`
`therefore V_(1)=(0.4xx100)/(0.05)=800`
`V_(2)-V_(1)=800-100 rArr 700 ml`.