For an unbiased coin how many possible outcomes are there for a coin tossed 8 times?
1. \(\rm^8C_2\)
2. 8!
3. 28
4. 82
1. \(\rm^8C_2\)
2. 8!
3. 28
4. 82
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Correct Answer – Option 3 : 28
Calculation:
While tossing a coin there are 2 possible outcomes (H or T), so for every toss possible cases are multiples by factor two.
Possible cases = [(H or T), (H or T), (H or T), (H or T), (H or T), (H or T), (H or T), (H or T) , i.e.,
Total cases = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 256 or 28