Find the value of
sin 405°
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To find: Value of sin 405°
We have,
sin 405° = sin [90° × 4 + 45°]
= sin 45°
[Clearly, 405° is in Ist Quadrant and the multiple of 90° is even]
= \(\frac{1}{\sqrt{2}}\) [∵ sin45° = \(\frac{1}{\sqrt{2}}\)]