Find the sum of all integers from 50 to 500 which I\’d divisible by 10
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a1=50d=10an=500500 = a + (n -1)d500 = 50 + 10n – 10500 – 40 = 10n460= 10nn = 46S46 = 46/2 {2×50 + (45)10 = 23(100 + 450) = 23×550 = 12650