Find the sum of all 2 digit numbers divisible by 3.
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All 2 digit numbers divisible by 3 are : 12, 51, 18, 21, …, 99.
This is an A.P. with a = 12 and d = 3.
Let it contain n terms.
Then, 12 + (n – 1) x 3 = 99 or n = 30.
Required sum = 30/2 x (12+99) = 1665.