Find the sum fo the first 22 terms of an AP whose first term is 4 and the common difference is `(4)/(3)`.
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Given that, `a= 4 and d = (4)/(3)`.
We have, `S_n = (n)/(2) [ 2a + (n-1)d]`
`S_(22) = ((22)/(2)) [(2)(4)+ (22 -1)((4)/(3))] = (11)(8+ 28) = 369`.