Find the radius of the circular section of the sphere `|vecr|=5` by the plane `vecr*(veci+vecj-veck)=4sqrt(3)`.

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The radius of the sphere is 5

The given plane is `x+y-z= 4sqrt(3)`

The length of the perpendicular from the centre (0, 0, 0) of the sphere on the plane `= (4sqrt(3))/(sqrt(1+1+1))= 4`.

Hence, radius of the circular section is `sqrt(25-16) = sqrt9 = 3 `