Find the perimeter of an isosceles triangle having area 100cm^2
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if a right angled triangle is an isosceles triangle.then base = perpendicular.let base = x cm1/2 × x × x = 100×2 = 200x = 10√ 2 cmThen the length of the hypotenuse = {tex}\\sqrt{x^2+\\;x^2}\\;=\\;\\sqrt{2x^2}\\;=\\;\\sqrt2\\;x{/tex}= 20Primeter of triangle = 10√ 2 + 10√ 2 + 20= 20 + 20√ 2= 20(1 + √ 2) cm