Find the nature of the roots of the quadratic equation 3x2 – 2√6 x + 2 = 0.
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Find the nature of the roots of the quadratic equation 3x2 – 2√6 x + 2 = 0.
Find the nature of the roots of the quadratic equation 3x2 – 2√6 x + 2 = 0.
3x2 – 2√6 x + 2 = 0
Compare given equation with the general form of quadratic equation, which is ax2 + bx + c = 0
a = 3, b = – 2√6, c = 2
Using Discriminant Formula:
D = b2 – 4ac
= (– 2√6)2 – 4 x 3 x 2
= 24 – 24
= 0
Roots of equation are real and equal.