Find the first term and the common difference of an AP, if the 3rd term is 6 and 17 th term is 34.
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If a is the first term and d is the common difference, then we have
`” “a + 2d = 6″ ” `(1)
`” ” a + 16 d = 34″ “` (2)
On substracting Eq. (1) from Eq. (2), we get
`” ” 14 d = 28 rArr d = 2`
Substituting the value of d in Eq. (1), we get `a= 2`
`therefore a = 2 and d = 2`.