Find the equation of the line through A(-2, 3) and perpendicular to the line through S(1, 2) and T(2, 5).
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Slope of ST = 5-2/ 2-1 = 3
Since the required line is perpendicular to ST, slope of required line = -1/3 and lines passes through A(-2,3)
Equation of the line in slope point form is y1 – y = m(x – x1)
The equation of the required line is y- 3 = -1/3 (x+2)
⇒ 3(y – 3) = -(x + 2)
⇒ 3y – 9 = -x – 2
⇒ x + 3y = 7