Fill in the blank
`””_(92)U^(235) +””_(0)n^(1) to ? +””_(36)^(92)Kr + 3″”_(0)^(1)n`
A. `._(52)^(137)Te`
B. `._(55)^(144)Cs`
C. `._(56)^(137)Ba`
D. `._(56)^(144)Ba`
`””_(92)U^(235) +””_(0)n^(1) to ? +””_(36)^(92)Kr + 3″”_(0)^(1)n`
A. `._(52)^(137)Te`
B. `._(55)^(144)Cs`
C. `._(56)^(137)Ba`
D. `._(56)^(144)Ba`
Correct Answer – d
`._(92)^(235)U + ._(0)^(1)n to ._(26)^(90)Kr + ._(56)^(144)Ba + 2 ._(0)^(1)n`