Correct Answer – C
Fifteen coupens are numbered `1,2,3,…15` respectively. Seven coupons are selected at random one at a time with replacement The Probability that the largest number appearing on a selected coupon is 9 is :
Preshita Pai
Asked: 3 years ago2022-11-04T21:08:25+05:30
2022-11-04T21:08:25+05:30In: General Awareness
Fifteen coupens are numbered `1,2,3,…15` respectively. Seven coupons are selected at random one at a time with replacement The Probability that the largest number appearing on a selected coupon is 9 is :
A. `((9)/(10))^(6)`
B. `((8)/(15))^(7)`
C. `((3)/(5))^(7)`
D. none of these
Fifteen coupens are numbered `1,2,3,…15` respectively. Seven coupons are selected at random one at a time with replacement The Probability that the largest number appearing on a selected coupon is 9 is :
A. `((9)/(10))^(6)`
B. `((8)/(15))^(7)`
C. `((3)/(5))^(7)`
D. none of these
A. `((9)/(10))^(6)`
B. `((8)/(15))^(7)`
C. `((3)/(5))^(7)`
D. none of these
Leave an answer
Leave an answer
Nidhi Chahal
Asked: 3 years ago2022-10-29T12:35:18+05:30
2022-10-29T12:35:18+05:30In: General Awareness
Fifteen coupens are numbered `1,2,3,…15` respectively. Seven coupons are selected at random one at a time with replacement The Probability that the largest number appearing on a selected coupon is 9 is :
A. `((9)/(196))^(6)`
B. `((8)/(15))^(7)`
C. `((3)/(7))^(7)`
D. None of these
Fifteen coupens are numbered `1,2,3,…15` respectively. Seven coupons are selected at random one at a time with replacement The Probability that the largest number appearing on a selected coupon is 9 is :
A. `((9)/(196))^(6)`
B. `((8)/(15))^(7)`
C. `((3)/(7))^(7)`
D. None of these
A. `((9)/(196))^(6)`
B. `((8)/(15))^(7)`
C. `((3)/(7))^(7)`
D. None of these
Leave an answer
Leave an answer
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Correct Answer – D
Since, there are 15 possible cases for selecting a coupor and seven coupons are selected, the total number o cases of selecting seven coupons =`15^7`
It is given that the maximum ·number on the selecte coupon is 9, therefore the selection is to be made from the coupons numbered 1 to 9. This can be made in r ways. Out of these `9^7` cases `8^7` does not contain the number 9.
Thus, the favourable number of cases `=9^7-8^7`
`therefore` Required probability `=(9^7-8^7)/(15^7)`
1,2,3,4,5,6,7,8,9
`=9^7-8^7`
`P=(9^7-8^7)/15^7`