Express the HCF of 210 and 66 as 210x+66y, where x,y are integers
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Applying Division lemma on 210 and 66210=66*3+2———–(1)Applying Division lemma on 2 and 6666=2*33+0Here remainder is zero\xa0so HCF(66,210)=2Now from(1)2=210-3*66HCF=210*1-3*66—————–(2)Given HCF=210x+66y————-(3)Comparing (2) and (3) we getx=1 and y=-3Hence HCF=210*1-3*66\xa0\xa0