Equation of the line passing through (1, 2) and parallel to the line y = 3x – 1 is
(A) y + 2 = x + 1
(B) y + 2 = 3 (x + 1)
(C) y – 2 = 3 (x – 1)
(D) y – 2 = x – 1
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Equation of the line passing through (1, 2) and parallel to the line y = 3x – 1 is
(A) y + 2 = x + 1
(B) y + 2 = 3 (x + 1)
(C) y – 2 = 3 (x – 1)
(D) y – 2 = x – 1
Equation of the line passing through (1, 2) and parallel to the line y = 3x – 1 is
(A) y + 2 = x + 1
(B) y + 2 = 3 (x + 1)
(C) y – 2 = 3 (x – 1)
(D) y – 2 = x – 1
Answer is (C)
Line is parallel to the line y = 3x – 1.
So, slope of the line is‘3’.
Also, line passes through the point (1,2).
So, equation of the line is: y – 2 = 3(x – 1)