Entropy change for reversible phase transition at constant pressure P and temperature T is calculated by the formula `DeltaS=(DeltaH)/(T),` where `DeltaH` is the enthalpy change for phase transition. For irreversible phase transition `DeltaSgt(DeltaH)/(T).`
Consider a phase transition.
`Sn(“white”,s)iffSn(“grey,s”)`
`DeltaH^(@) `at 1 atm and` 300K=-2 kJmol^(-1)`
The equilibrium temperature at 1 atm is 400 K.
Assume `C_(p,m)` of Sn (white,s) and Sn(grey,s) are equal.
`DeltaS^(@)` for above phase transition at 1 atm and 300K is :
A. `-5JK^(-1)mol^(-1)`
B. `-(20)/(3)JK^(-1)mol^(-1)`
C. `-0.0055JK^(-1)mol^(-1)`
D. `-(2000)/(3)JK^(-1)mol^(-1)`
Consider a phase transition.
`Sn(“white”,s)iffSn(“grey,s”)`
`DeltaH^(@) `at 1 atm and` 300K=-2 kJmol^(-1)`
The equilibrium temperature at 1 atm is 400 K.
Assume `C_(p,m)` of Sn (white,s) and Sn(grey,s) are equal.
`DeltaS^(@)` for above phase transition at 1 atm and 300K is :
A. `-5JK^(-1)mol^(-1)`
B. `-(20)/(3)JK^(-1)mol^(-1)`
C. `-0.0055JK^(-1)mol^(-1)`
D. `-(2000)/(3)JK^(-1)mol^(-1)`
Correct Answer – a