Divide 39 in two parts such that their product is 324. How to solve
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Let first number be xLet the second number be 39-xAccording to the question,(x) (39-x) =32439x-x²=324-x²+39x-324=0-(x²-39x+324)x²-39x+324=0Now splitting the middle termx²-27x+12x+324=0x(x-27)+12(x-27)x=27 or x=-12….I hope this helps you ?
I2+27=39 and 12×27=324
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