Home/ Questions/Q 465847
Next
In Process
Kalpit Jacob
Asked: 2022-11-07T17:22:03+05:30 In:

Disintegration constant of a radioactive material is `lambda`:
A. Its half life equal to `(log_(e)2)/(lambda)`
B. It mean life equals to `(1)/(lambda)`
C. At time equal to mean life, `63%` of the Initial radioactive material is left undecayed
D. After `3-` half 1/3 rd of the initial radioactive material is left undecayed.

Disintegration constant of a radioactive material is `lambda`:
A. Its half life equal to `(log_(e)2)/(lambda)`
B. It mean life equals to `(1)/(lambda)`
C. At time equal to mean life, `63%` of the Initial radioactive material is left undecayed
D. After `3-` half 1/3 rd of the initial radioactive material is left undecayed.
Parabola
Leave an answer

Leave an answer

Browse

1 Answer

  1. Correct Answer – A::B
    `N = N_(0)e^(-lambdat) rArr (N_(0))/(10) = N_(0)e^(-lambdaT_(1//2))`
    `rArr T_(1//2) = (log_(e)2)/(lambda) rArr T_(mean) = (1)/(lambda)`

    • 0