Derivation of potential energy
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We know that w=f*s Work is equal to potential energyAccording to newton\’s second law of motion,f=m*a So in w=f*sP.E. = m*a*s We know that a=g So, P.E. = m*g*ss=h (distance covered) This concludes thatP.E. = m*g*h
W=force ×displacement mg×h W=mgh PE=mgh