ΔABC =ΔDEF having area of 64 and 81 and D= 9 find AB
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DE=9,AB=?Now as area is different so triangle cannot be congruent\xa0so are similar{tex}\\begin{array}{l}Now\\;\\triangle ABC\\;\\sim\\triangle DEF\\\\\\frac{ar(\\triangle ABC)}{ar(\\triangle DEF)}=\\frac{AB^2}{DE^2}\\\\\\frac{64}{81}=\\frac{AB^2}{9^2}\\\\AB^2=64\\\\AB=8\\end{array}{/tex}
Yes it mean congurent
What yes….congurent ya similar???
Yes
By ” = ” do you mean congurent or similar