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Sukriti Sibal
Asked: 2022-11-10T21:24:31+05:30 In:

Crude calcium carbide is made in an electric furance by the following reactions:
`CaO+3CtoCaC_2+CO`. The product contains `85%` of `CaC_2` and `15%` unreacted CaO.
(a). How much CaO is to be added to the fur

Crude calcium carbide is made in an electric furance by the following reactions:
`CaO+3CtoCaC_2+CO`. The product contains `85%` of `CaC_2` and `15%` unreacted CaO.
(a). How much CaO is to be added to the fur
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  1. (a). `CaO+3CtoCaC_2+CO`
    All the CaO is not used up. Calculate how much CaO is required for 85 g of `CaC_2`. That much CaO plus 15 g excess should be taken. 15 g remains as it is.
    `64 g of CaC_2-=56g of CaO`
    `therefore85g of CaC_2-=56g of CaC`
    `therefore85g of CaC_2-=56xx(85)/(64)=74.374 g of CaO`
    Total `CaO-=74.347+15=89.374g`
    For each 85 g of pure `CaC_2` and 100 g of impure `CaC_2`.
    85 kg pure `CaC_2=89.374kg of CaO`
    `1000kg pure CaCl_2=(89.374xx1000)/(85)`
    `=1051.46kg of CaO`
    (b). `100 kg` crude `CaC_2=89.374kg CaO`
    `therefore1000kg` crude `CaC_2=893.74kg CaO`

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