Cos thetha=0.6, show that (5sin thetha-3tan thetha) =0.
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Given=cosA=0.6CosA=B/H0.6=B/H6/10=B/HBase=6Hypo.=10then by using pythagoras theorem Perpendicular =8Prove:5sinA-3tanA=05×P/H-3×P/B=05×8/10-3×8/6=04-4=00=0Hence proved